find value of p abp=(3a-b)whole square - (3a-b) whole square
Answers
Answered by
1
p=0 since abp=(3a-b)^2-(3a-b)^2
abp=(3a-b)(3a+b)-(3a-b)(3a+b)
abp=9a^2 + 3ab -3ab - b^2 -(9a^2+3ab-3ab-b^)
abp=0
p=0
abp=(3a-b)(3a+b)-(3a-b)(3a+b)
abp=9a^2 + 3ab -3ab - b^2 -(9a^2+3ab-3ab-b^)
abp=0
p=0
Similar questions