Question

Find value of 'p' for which px²+6x+2 =0 has both real roots.


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Answer 1

Step-by-step explanation:

For real roots , D=0 ( d=b² - 4ac)

b² - 4ac = 0

6² - 4(p)(2) = 0

36 - 8p = 0

-8p = - 36

p= -36/-8

p= 9/2

Answer 2

a= p
b= 6
c=2
b^2-4ac=0
6^2-4(p)(2)=0
36-8p=0
36=8p
36/8=p

Hope it helpsss!!!!