find value of p for which the quadratic equation is px (x-3)+ 9 = 0 has equal root
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Answer:
Expanding it gives:
px^2-3px+9=0
To obtain equal root, discriminant must equal 0:
Discriminant=(-3p)^2-4(p)(9)=9p^2-36p
∴9p^2-36p=0
9p(p-4)=0
9p=0 or p-4=0
p=0 or p=4
Since p=0 is not plausible, p=4 is the solution.
Hope this helps :)
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