Question

find value of p for which the quadratic equation is px (x-3)+ 9 = 0 has equal root

Answer 1

Answer:

Expanding it gives:

px^2-3px+9=0

To obtain equal root, discriminant must equal 0:

Discriminant=(-3p)^2-4(p)(9)=9p^2-36p

∴9p^2-36p=0

9p(p-4)=0

9p=0 or p-4=0

p=0 or p=4

Since p=0 is not plausible, p=4 is the solution.

Hope this helps :)

Step-by-step explanation: