find value of p for which the quadratic equation x(x-4)+p=0
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We know that d = b^2 - 4 * a * c
= (-4)^2 - 4 * 1 * p = 0
= 16 - 4p = 0
p = 4.
Hope this helps!
= (-4)^2 - 4 * 1 * p = 0
= 16 - 4p = 0
p = 4.
Hope this helps!
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