Question

find value of p if the following quadratic equation have equal roots

xsquare-(p-3)x+p=0
​

Answer 1

Answer:

hey frnd here is your answer

Step-by-step explanation:

• D=b²-4ac.

• Equation is X²-(p-3)x+p=0.

• here a=1, b= -(p-3) ,c=p

• b²-4ac=0

• [-(p-3)²]-4(1)(p)=0.

• (p-3)²=4p

• p²-6p+9=4p

• p²-10p+9

• (p-9)(p-1)

• so P=9 and P=1.

so your final answer is-

p=9 and P=1.

I hope you get the right answer

thanks for asking

plzz mark as brainlist...

Answer 2

Answer:

$\large{\red{\underline{\tt{Answer}}}}$

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QUETION:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$x ^{2} - (p - 3)x + p = 0$

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ANSWER:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

$x ^{2} - xp ^{2} - 3x ^{2} + 3xp$