Question

find value of p if x=2 y=3 in (P+1)x-(2p+3)y-1=0​

Answer 1

Answer:

By substituting the values of x=2 and y=3 in the equation (P+1)x-(2p+3)y-1=0

we get,

(p+1)2-(2p+3)3-1=0

2p+2-6p+9-1 =0

10-4p =0

-4p =0-10

-4p =-10

p= -10/-4

p= 5/2

p= 2.5