Question

Find value of p so that quadratic equation px(x-3)+9=0 has two equal roots

Answer 1

The value of p that makes the roots of the quadratic equation equal is p=4.

In order for a quadratic equation to have two equal roots, the discriminant must equal zero, which is determined by the formula b^2-4ac=0, where a, b, and c are the coefficients in equation $ax^{2}$+bx+c=0.

In this case, a=p, b=p(3), and c=9, so substituting these values into the discriminant formula gives:

p(3)^2 - 4p * 9 = 0.

Expanding and solving for p, we find that:

9$p^{2}$ - 36p = 0.

Dividing both sides by 9, we get:

$p^{2}$ - 4p = 0.

Factoring the left side, we get:

(p-4)p = 0.

So either p=0 or p=4.

However, p cannot be 0 because it would make the equation degenerate to 9=0, which is not possible.

For more such questions on the quadratic equations: https://brainly.in/question/48877157

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