Find value of p when quadratic equation is p x(x-3)+9=0 has two roots
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Answer:
Expanding it gives:
px^2-3px+9=0
To obtain two roots, the discriminant must be bigger than 0
Discriminant=(-3p)^2-4(p)(9)=9p^2-36p
∴9p^2-36p>0
9p(p-4)>0
p<0, p>4
∴p⊂(-∞,0)∪(4,∞)
Hope this helps :)
Step-by-step explanation:
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