Question

Find value of polynomial 27x^2–x+1 if x=1/3

Answer 1

Answer:

13/3

Step-by-step explanation:

27 (1/3)^2 - (1/3) + 1 = 27(1/9) - (1/3) + 1 = 3 + 1/3 +1

= 4 + 1/3 = 13/3

Answer 2

Step-by-step explanation:

$p(x) = 27 {x}^{2} - x + 1$

$putting \: the \: value \: of \: x = \frac{1}{3}$

$p( \frac{1}{3} ) = 27( \frac{1}{3} )^{2} - \frac{1}{3} + 1$

$= 27( \frac{1}{9} ) - \frac{1}{3} + 1$

$= 3 - \frac{1}{3} + 1$

$= \frac{9 - 1}{3} + 1$

$= \frac{8}{3} + 1$

$= \frac{8 + 3}{3}$

$= \frac{11}{3}$

hope it helps :)