Question

find Value of Polynomial P(x) = kx^2+1. If one
Zeroes is -1​

Answer 1

$p(x) = kx {}^{2} + 1 \\ \\ x = - 1 \\ \\ \\ = > p( - 1) = k( - 1) {}^{2} + 1 \\ = > p( - 1) = k + 1$

i hope that helps you

Answer 2

Answer:

P(-1)=k+1

k=-1

Step-by-step explanation:

p(x)=kx^2+1

P(-1)=k(-1)^2+1=0

P(-1)=k+1=0

k=-1