Find value of polynomial
![{t}^{2} + {3t}^{2} \: \: \: if \: t = 0 {t}^{2} + {3t}^{2} \: \: \: if \: t = 0](https://tex.z-dn.net/?f=+%7Bt%7D%5E%7B2%7D++%2B++%7B3t%7D%5E%7B2%7D++%5C%3A++%5C%3A++%5C%3A+if+%5C%3A+t+%3D+0)
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Expression :-
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Given :-
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Solution :-
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Procedure :-
→ This Question is from the polynomials.
→ We will put 0 in place of t and then we will equate the whole expression.
→ Then after equating to he whole expression we will do the square of 0 that will be 0 and then we will multiply the 3 with 0 then again we will have 0.
→ Then after we will add 0 with 0 then, the final answer is 0.
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