Find value of polynomial (x-2)^2-(x+2)^2
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(x-2)^2=x^2+4-2(X)(2)=x^2-4x+4 - 1
(x+2)^2=x^2+4+4x-2
1-2
=-8x
Answered by
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Answer:
-8x
Step-by-step explanation:
(x-2) ^2-(x+2)^2
formula:- (a-b) ^2= a^2-2ab+b^2
(a+b) ^2=a^2+2ab+b^2
so(x-2) ^2-(x+2)^2= x^2-4x+4-x^2-4x-4
=-8x
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