Math, asked by suryapratapsingha524, 17 days ago

find value of r in 3^r÷3^-2=3^6​

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Answered by Anonymous
4

Answer:

S = ∑r = 16^30(r + 2)(r - 3) = ∑r = 1^30(r + 2)(r - 3) - ∑r = 1^15(r + 2)(r - 3) = ∑r = 1^30(r^2 - r - 6) - ∑r = 1^15(r^2 - r - 6) [By using ..

Answered by Anonymous
3
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