Math, asked by prachipiyusha, 1 year ago

find value of R when
√25×25+50×50+2×25×50×cos120

Answers

Answered by shadowsabers03
1
cos 120 = -\frac{1}{2}

\sqrt{25 * 25 + 50 * 50 + 2 * 25 * 50 * (-\frac{1}{2})}
= \sqrt{(25^2 + 50^2 + 2 * 25 * 50) * (-\frac{1}{2})}
= \sqrt{(25 + 50)^2 * (-\frac{1}{2})}
= \sqrt{75^2 * (-\frac{1}{2})}
= 75\sqrt{-\frac{1}{2}}

Hope this will be helpful. 

prachipiyusha: n the answer given behind is 27.4 degree
prachipiyusha: kindly help me out with this sum
shadowsabers03: Any problem?
prachipiyusha: ??
shadowsabers03: Any problem in my calculation?
prachipiyusha: ans is 27 .84
shadowsabers03: How?
prachipiyusha: i2dk
shadowsabers03: Then where did you get it?
prachipiyusha: back of solution
Similar questions