Math, asked by deepakkuma9507, 1 year ago

Find value of root 48 plus root 32 by root 27 plus root 18

Answers

Answered by abhi569
5

\dfrac{\sqrt{48}+\sqrt{32}}{\sqrt{27}+\sqrt{18}}


Spitting the terms in their product form,or factorizing them.


\dfrac{\sqrt{2\times2\times2\times2\times3}+\sqrt{2\times2\times2\times2\times2}}{\sqrt{3\times3\times3}+\sqrt{2\times3\times3}}


We know, \sqrt{x\times x\times x\times} = x\sqrt{x}


\dfrac{4\sqrt{3}+4\sqrt{2}}{3\sqrt{3}+3\sqrt{2}}


\dfrac{4(\sqrt{3}+\sqrt{2})}{3(\sqrt{3}+\sqrt{2})}


Removing √3 + √2


\dfrac{4}{3}




Therefore, the value of root 48 plus root 32 by root 27 plus root 18 is 4 / 3

Answered by khushibargohil
2

Step-by-step explanation:

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