Find value of sec(-1125
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Answer:
- (1)/(2)^1/2
Step-by-step explanation:
Since Sin (-θ) = - Sinθ, we have
Sin(-1125) = - Sin (1125)
= -Sin(1080 + 45) (because 3 x 360 = 1080
Now Sin(n x 2π) = 0 and Cos (n x2π) = 1 ( n is any integer )
= Sin (1080 + 45)
= -(Sin1080Cos45 + Cos1080Sin45)
= - ( 0 + 1*(1/2^1/2)
= - 1 upon root 2
= - (1)/(2)^1/2
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