Question

find value of sin 0+cos 30-tan 45+cosec60+cot 90

Answer 1

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Answer 2

The value of the required expression is $\frac{7\sqrt{3}-6}{6}$.

Step-by-step explanation:

Consider the provided information.

$\sin 0+\cos 30-\tan 45+\cosec 60+\cot 90$

Using trigonometric values: $\sin 0=0,\cos 30=\frac{\sqrt{3}}{2},\tan 45=1,\csc 60=\frac{2}{\sqrt{3}}\ and\ \cot 90=0$

$0+\frac{\sqrt{3}}{2}-1+\frac{2}{\sqrt{3}}+0$

$\frac{\sqrt{3}}{2}-1+\frac{2}{\sqrt{3}}$

$\frac{3-2\sqrt{3}+4}{2\sqrt{3}}$

$\frac{7-2\sqrt{3}}{2\sqrt{3}}$

Rationalize the above expression.

$\frac{7-2\sqrt{3}}{2\sqrt{3}}\times\frac{2\sqrt{3}}{2\sqrt{3}}$

$\frac{14\sqrt{3}-12}{12}$

$\frac{7\sqrt{3}-6}{6}$

Hence, the value of the required expression is $\frac{7\sqrt{3}-6}{6}$.

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All trignometric identities

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