Question

find value of sin (19π/3)​

Answer 1

Step-by-step explanation:

$\sin( \frac{19\pi}{3} ) \\ = \sin(19 \times 60) \\ = \sin(1140) \\ = \sin(90 \times 12 + 60) \\ = \sin(60 ) \\ = \frac{ \sqrt{3} }{2}$

val is positive as it lies in first quadrant....

HOPE IT HELPS..... PLZ MARK BRAINLIEST

Answer 2

$\large\underline{ \underline{ \sf \: Solution : \: \: \: }}$

$\star$Sin (19π/3)

Firstly , we have to convert 19π/3 radian into degree measure

$\sf \large \fbox{\fbox{Degree \: measure = \frac{180}{\pi} \times radian \: measure}}$

$= \frac{180}{\pi} \times \frac{19\pi}{3} \\ \\ = 60 \times 19 \\ \\ = 1140 \degree$

So , Sin (19π/3) = Sin (1140)

Now ,

$\sf \implies Sin \: (1140) \\ \\ \sf \implies Sin \: (360 × 3 + 60) \\ \\ \sf \implies Sin \: (60) \\ \\ \sf \implies \sqrt{3}/2$

$\therefore$ The required value is √3/2

$\large\underline{ \underline{ \sf \: Remmember : \: \: \: }}$

$\star \: \: \sf Sin \: ( 360 × n + \theta ) = Sin \: ( \theta)$