find value of sin 22
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0.374607 is value of sin22°
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22½° lies in the first quadrant.
Therefore, sin 22½° is positive.
For all values of the angle A we know that,cos A = 1 - 2 sin2 A2
1 - cos A = 2 sin22 A2A2
⇒ 2 sin22 A2A2 = 1 - cos A
⇒ 2 sin22 22½˚ = 1 - cos 45°
⇒ sin22 22½˚ = 1−cos45°21−cos45°2
⇒ sin22 22½˚ = 1−12√21−122, [Since we know cos 45° = 1√21√2]
⇒ sin 22½˚ = 12(1−12√)−−−−−−−−√12(1−12), [Since, sin 22½˚ > 0]
⇒ sin 22½˚ = 2√−122√−−−−√2−122
⇒ sin 22½˚ = 122−2–√−−−−−−√122−2
Therefore, sin 22½˚ = 122−2–√−−−−−−√
Therefore, sin 22½° is positive.
For all values of the angle A we know that,cos A = 1 - 2 sin2 A2
1 - cos A = 2 sin22 A2A2
⇒ 2 sin22 A2A2 = 1 - cos A
⇒ 2 sin22 22½˚ = 1 - cos 45°
⇒ sin22 22½˚ = 1−cos45°21−cos45°2
⇒ sin22 22½˚ = 1−12√21−122, [Since we know cos 45° = 1√21√2]
⇒ sin 22½˚ = 12(1−12√)−−−−−−−−√12(1−12), [Since, sin 22½˚ > 0]
⇒ sin 22½˚ = 2√−122√−−−−√2−122
⇒ sin 22½˚ = 122−2–√−−−−−−√122−2
Therefore, sin 22½˚ = 122−2–√−−−−−−√
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