Question

find value of sin (60deg.+ thita)-cos (30deg.-thita)

Answer 1

Sin(90°-a)=Cos(a)

Let Theta =a

So Sin[90°-(60°+a)]=cos(30°-a)

→Sin(60°+a)-cos(30°-a)=
=cos(30°-a)-cos(30°-a)=
=0

So Your answer is zero [0].

Hope It Helps...
Regards,
Leukonov.