find value of tan-1(1/11)+cot-1(6/5)
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0
Answer:
Correct option is C)
tan
−1
6
5
+
2
1
tan
−1
60
11
2
1
tan
−1
(
1−(
6
5
)
2
6
5
×2
)+
2
1
tan
−1
(
60
11
)[∵2tan
−1
x=tan
−1
1−x
2
2x
]
=
2
1
tan
−1
(
11
60
)+
2
1
tan
−1
(
60
11
)
=
2
1
[cot
−1
(
60
11
)+tan
−1
(
60
11
)][tan
−1
x=cot
−1
x
1
]
=
2
1
×
2
π
=
4
π
Because[cot
−1
x+tan
−1
x=
2
π
]
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