Question

Find value of tan 15°

Answer 1

MARK BRAINLIEST.

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Answer 2

$\tan15 \\ \\ = > \tan(45 - 30) \\ \\ = > \frac{ \tan45 - \tan30 }{1 + \tan45 \tan30 } \\ \\ = > \frac{1 - \frac{1}{ \sqrt{3} } }{1 + 1. \frac{1}{ \sqrt{3} } } \\ \\ = > \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 }$