find value of tan(sin inverse(3/5)+ cot inverse(3/2))
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Step-by-step explanation:
calculations=>
sinA= 3/5=> tanA= 3/√ ( 5²-5²)= 3/4
=> sin inv(3/5)= tan inv(3/4)
again cot inv3/2)= tan inv ( 2/3)
thus
tan[ sin inv(3/5).+ cot in(3/2)]
tan inv tan(3/4) + tan inv( tan (2/3)
= 3/4+2/3= 17/12
= 1 integer 5/12 is the ans
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