find value of the following using log tables ((6.284)(624)^1÷2)÷(0.005)^1÷4
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How do I solve this equation using log tables?
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We will solve it partwise.
First of all let us suppose,
(35.285)^2 = a
Taking log of both sides
2 log (35.285) = log a
3.0952 = log a
Now taking antilog
antilog (3.0952) = a
=> 1245.09 = a ........(i)
Similarly let us suppose
(23..45)^3 = b
Taking log we get
4.1104 = log b
Now take antilog
12895.3 = b .........(ii)
Adding (i) and (ii)
We get value of expression inside cube root.
Now let us suppose (a+b)^1/3 = x
=> (14140.39)^1/3 = x
Taking log
1/3 log (14140.39) = log x
=> 1.3835 = log x
Now take antilog to get value of x.
X = 24.182
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