Question

Find value of the question ​

Answer 1

$9 \div 3 \times { \cot() }^{2} 30 + 3 \sin {}^{2} 30 + 2 { \csc }^{2} 60 - 3 \div 4 \tan {}^{2} 30 = \\ = 3 \sqrt{3 {}^{2} } + 3 \times 1 \div 4 - 2 \times 4 \div 3 - 3 \div 4 \times 1 \sqrt{3 {}^{2} } \\ = 9 + 3 \div 4 - 8 \div 3 - 1\div 4 \\ = (108 + 9 - 32 - 3) \div 12 \\ = 82 \div 12 = 41 \div 6$

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