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Answer- x= 1-√2
1/x= 1/(1-√2)
Rationalising the denominator
1/(1-√2)= {1/(1-√2)}× {(1+√2)/(1+√2)}
= (1+√2)/{ 1² -(√2)²}
= (1+√2)/ (1-2)
= (1+√2)/ -1
= -1-√2
x-1/x= 1-√2-(-1-√2)
= 1-√2+1+√2
= 2
Pl. mark as the BRAINLIEST answer..
1/x= 1/(1-√2)
Rationalising the denominator
1/(1-√2)= {1/(1-√2)}× {(1+√2)/(1+√2)}
= (1+√2)/{ 1² -(√2)²}
= (1+√2)/ (1-2)
= (1+√2)/ -1
= -1-√2
x-1/x= 1-√2-(-1-√2)
= 1-√2+1+√2
= 2
Pl. mark as the BRAINLIEST answer..
BrainlyYoda:
I am surprised to know that you added those brackets in just 22.13 seconds. Well done:) And also i didn't expected such a precise timing which you told me.
=_= Donot ___. I didn't do anything.
:(
:( Don't be sad..
Answered by
7
The answer is given below :
Given that,
x = 1 - √2
Now,
1/x = 1/(1 - √2)
We rationalise the denominator by multiplying both the denominator and numerator by (1 + √2)
So,
1/x = {1/(1 - √2)} × {(1 + √2)/(1 + √2)}
= (1 + √2)/(1 - 2)
= (1 + √2)/(- 1)
= - (1 + √2)
Thus,
x - 1/x
= (1 - √2) - {- (1 + √2)}
= 1 - √2 + 1 + √2
= 2
Identity rule used :
(a + b)(a - b) = a² - b²
Thank you for your question.
Given that,
x = 1 - √2
Now,
1/x = 1/(1 - √2)
We rationalise the denominator by multiplying both the denominator and numerator by (1 + √2)
So,
1/x = {1/(1 - √2)} × {(1 + √2)/(1 + √2)}
= (1 + √2)/(1 - 2)
= (1 + √2)/(- 1)
= - (1 + √2)
Thus,
x - 1/x
= (1 - √2) - {- (1 + √2)}
= 1 - √2 + 1 + √2
= 2
Identity rule used :
(a + b)(a - b) = a² - b²
Thank you for your question.
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