Math, asked by ahanachaudhuri1002, 9 hours ago

find value of x : 1/x-1/x+b=1/a-1/a+b​

Answers

Answered by nishankumarmmk
1

Answer:

(1/a)+b+x =(1/a)+(1/b)+(1/x)

or. (1/a)-(1/a)+b+x= (1/b)+(1/x)

or. b+x=(1/b)+(1/x)

or. x+b=(x+b)/bx

or. (x+b) - (x+b)/bx =0

or. (x+b).(1–1/bx)=0

Either x+b=0 => x =-b

Or 1 -1/bx =0. => x=1/b.

x = -b and 1/b. Answer.

If the given question is as follows:-

1/(a+b+x) = (1/a)+(1/b) +(1/x)

or. 1/(a+b+x) -1/x=1/a+1/b

or(x-a-b-x)/x.(a+b+x)=(b+a)/a.b

or. -(a+b)/x.(a+b+x)=(b+a)/a.b

or. -1/x.(a+b+x) = 1/a.b

or. x.(a+b+x) = -ab

or. x^2+(a+b).x+ab=0

or. x^2+ax+bx+ab=0

or. x(x+a)+b(x+a)=0

or. (x+a).(x+b)=0

or. x= -a and. -b. Answer.

Step-by-step explanation:

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Answered by anamika8031
0

x can be any integer

Step-by-step explanation:

in the eqn 1/x and 1/b are cancelled out. The remaining b will be the rhs &lhs. so, the variable x doesn't indicate a specific value, it may a positive or negative integer..

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