find value of x : 2x square+ ax+ a square=0
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The valve of x is
x=(-a+-√a²-8a)/4
The above equation is in the form of
ax²+bx+c=0
the value of x is
x= (-b±√b²-4ac)/2a
x=(-a+-√a²-8a)/4
The above equation is in the form of
ax²+bx+c=0
the value of x is
x= (-b±√b²-4ac)/2a
ajeetmohanty20pchek8:
i need the procedure
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