find value of x^3-x^2+x+46 if x=2+3i
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Answer: putting value of x
(2+3i)^3 - (2+3i)^2 +(2+3i) +46
(2+3i)[(2+3i)^2-(2+3i)+1]+46
(2+3i)[4+3i^2+12i-2+3i+1] +46
Usingi^2=1
(2+3i)[4-9+12i -2 +3i +1]+46
(2+3i)[9i-7+1]+46
18i-14-27i^2-21i+46+2+3i
Usingi^2=1
32-3i+27+2+3i
61
Step-by-step explanation:
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