Question

Find value of x
4 root 3x+1 = 2​

Answer 1

Answer:

$4 \sqrt{3x + 1} = 2$

$\sqrt{3x + 1} = \frac{1}{2}$

$squaring \: on \: both \: sides$

$({ \sqrt{3x + 1}) }^{2} = ( { \frac{1}{2}) }^{2}$

$3x + 1 = \frac{1}{4}$

$3x = \frac{1}{4} - 1$

$3x = - \frac{3}{4}$

$x = - \frac{1}{4}$

Answer 2

Answer:

x=5

Step-by-step explanation:

4root 3x+1=2

(taking 2 time square Bothside)

3x+1=2^4

3x+1=16

3x=16-1

x=15/3

x=5