find value of x and all three angles of triangle if angles are (2x-1°) (x+25°) (3x+12°)
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Answered by
4
By angle sum property of triangle,
2x - 1 + x + 25 + 3x + 12 = 180
=> 6x + 36 = 180
=> 6x = 180 - 36
=> 6x = 144
=> x = 24
First angle = 2 (24) - 1 = 48 - 1 = 47°
Second angle = 24 +25 = 49
Third angle = 3 (24) + 12 = 72 + 12 = 84°
2x - 1 + x + 25 + 3x + 12 = 180
=> 6x + 36 = 180
=> 6x = 180 - 36
=> 6x = 144
=> x = 24
First angle = 2 (24) - 1 = 48 - 1 = 47°
Second angle = 24 +25 = 49
Third angle = 3 (24) + 12 = 72 + 12 = 84°
Answered by
5
HEYA!!
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➡Use angle Sum Property of a Triangle ,
( 2 x - 1 ) + ( x + 25 ) + ( 3x + 12 ) = 180
6x - 1 + 25 + 12 = 180
6x + 36 = 180
6x = 144
x = 144/6
x = 24°
➡Angles are :
✨ ( 2 × 24 - 1 ) = 47°
✨ ( 24 + 25 ) = 49°
✨ ( 3 × 24 + 12 ) = 84°
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➡Use angle Sum Property of a Triangle ,
( 2 x - 1 ) + ( x + 25 ) + ( 3x + 12 ) = 180
6x - 1 + 25 + 12 = 180
6x + 36 = 180
6x = 144
x = 144/6
x = 24°
➡Angles are :
✨ ( 2 × 24 - 1 ) = 47°
✨ ( 24 + 25 ) = 49°
✨ ( 3 × 24 + 12 ) = 84°
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