find value of x and y.
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3/(x+3)-2/(y-3)= -1/2
9/(x+3)-6/(y-3)= -3/2
9/(x+3)+1/(y-3)=2
subtracting,
-6/(y-3)-1/(y-3)= -3/2-2
=> -7/(y-3)=(-3-4)/2
=> -7/(y-3)= -7/2
=> 1/(y-3)=1/2
=> y-3=2
=> y=2+3=5
putting the value y=5 , in the 2nd equation
9/(x+3)+1/(5-3)=2
=> 9/(x+3)+1/2=2
=> 9/(x+3)=2-1/2=(4-1)/2
=> 9/(x+3)=3/2
=> 3(x+3)=9×2
=> x+3=3×2=6
=> x=6-3
=> x=3
so, x=3 , y=5
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