Math, asked by stud26, 1 month ago

find value of x and y.

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Answers

Answered by bagkakali
1

Answer:

3/(x+3)-2/(y-3)= -1/2

9/(x+3)-6/(y-3)= -3/2

9/(x+3)+1/(y-3)=2

subtracting,

-6/(y-3)-1/(y-3)= -3/2-2

=> -7/(y-3)=(-3-4)/2

=> -7/(y-3)= -7/2

=> 1/(y-3)=1/2

=> y-3=2

=> y=2+3=5

putting the value y=5 , in the 2nd equation

9/(x+3)+1/(5-3)=2

=> 9/(x+3)+1/2=2

=> 9/(x+3)=2-1/2=(4-1)/2

=> 9/(x+3)=3/2

=> 3(x+3)=9×2

=> x+3=3×2=6

=> x=6-3

=> x=3

so, x=3 , y=5

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