Question

find value of x and y 8^x×4^y=1
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Answer 1

Step-by-step explanation:

$\huge\underline\blue{Answer:-}$

${8}^{x}×{4}^{y}=1\\=>4({2}^{x}×{1}^{y})=1\\=>{4}^{x+y}=1\\=>x=4\\y=1$

Answer 2

Answer:

your answer is here and don't follow to me so answer is...

Step-by-step explanation:

(8)^{x}