CBSE BOARD X, asked by user32537247372, 1 year ago

find value of x and y in these equations​

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Answered by pervaiz14
0

3x-3y=5xy--(1)

6x-5y=-2xy--(2)

FROM --(1)

X=5XY+3Y/3

IN (2)

6(5XY+3Y/3)-5Y=(-2XY)

(30XY+18Y/3)-5y=(-2XY)

30XY+18Y-5Y=(-2XY)*3

30XY+13Y=(-6XY)

30XY+6XY+13Y=0

36XY+13Y=0

Y=

Answered by shailjaaaa
0

first multiply equation 1 by 5 then equation II by 3

which will give you two equations again, with the term of y cancelling out .

27x=31xy

y=27/31

now, keep the value of y in first equation:

8x-3(27/31)=5x(27/31)

8x-(81/31)=(135x/31)

8x-(135x/31)=81/31

248x-135x=81

113x=81

x=81/113.

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