find value of x by completing the square in x^2-3x-10=0
Answers
Answered by
2
Answer:
x=5,x=-5
Step-by-step explanation:
x^2-3x-10=0......(1)
x^2-2.3/2x=10,
adding( 3/2)^2 on both sides we get,,
x^2-2.3/2.x+(3/2)^2=10+(3/2)^,
it is in the form of a^2-2.ab+b^2= (a-b)^2,
(x-3/2)^2=10+9/4,
(x-3/2)^2=49/4,
x-3/2=+or-7/2,
x=+or-7/2+3/2,
x=+ or-10/2,
x= 5or-5.
Similar questions
Math,
5 months ago
Chemistry,
5 months ago
CBSE BOARD X,
10 months ago
Hindi,
10 months ago
Chemistry,
1 year ago