Question

find value of x fast plz​

Answer 1

$\underbrace{\underline {\boxed{ \sf \underline {\underline{\green{ SOLUTION}}}}}}$

$\tt { - 5}^{x + 1} \times {( - 5)}^{5} = ( \frac{ - 1}{5} {)}^{ - 7} \\ \tt by \: using \: {a}^{m} \times {a}^{n} = {a}^{m + n} \: and \: \\ \tt ({ \frac{a}{b}) }^{ - c} = { \frac{b}{a} }^{c} we \: have \\ \tt \longrightarrow{ - 5}^{x + 1 + 5} = {( - 5)}^{7} \\ \tt \longrightarrow { - 5}^{x + 6} = { - 5}^{7} \\ \tt \longrightarrow { \cancel{- 5}}^{x + 6} = { \cancel{- 5}}^{7} \\ \tt \longrightarrow x + 6 = 7 \\ \tt \longrightarrow x = 7 - 6 = 1 \\ \\ \\ \\ \\ \tt Hence, \huge \boxed{ \tt x = 1}$

Answer 2

Answer:

$\begin{gathered}\tt { - 5}^{x + 1} \times {( - 5)}^{5} = ( \frac{ - 1}{5} {)}^{ - 7} \\ \tt by \: using \: {a}^{m} \times {a}^{n} = {a}^{m + n} \: and \: \\ \tt ({ \frac{a}{b}) }^{ - c} = { \frac{b}{a} }^{c} we \: have \\ \tt \longrightarrow{ - 5}^{x + 1 + 5} = {( - 5)}^{7} \\ \tt \longrightarrow { - 5}^{x + 6} = { - 5}^{7} \\ \tt \longrightarrow { \cancel{- 5}}^{x + 6} = { \cancel{- 5}}^{7} \\ \tt \longrightarrow x + 6 = 7 \\ \tt \longrightarrow x = 7 - 6 = 1 \\ \\ \\ \\ \\ \tt so, \huge \boxed{ \tt x = 1}\end{gathered}$