Math, asked by pilotsd, 1 year ago

find value of x for which 2^3x =log16base2

Answers

Answered by Thatsomeone
1
Hey user

Here is your answer :-

 {2}^{3x}  =   log_{2}(16)  \\  \\  {2}^{3x}  =  log_{2}( {2}^{4} )  \\  \\  {2}^{3x}  = 4 log_{2}(2)  \\  \\  {2}^{3x}  = 4 \\  \\  {2}^{3x}  =  {2}^{2}  \\  \\ 3x = 2 \\  \\ x =  \frac{3}{2}

thank you.
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