find value of x if AB ll EF. given values are angle ABC=70° angle DFE=40°
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Answered by
21
HELLO !!
HERE IS YOUR ANSWER,
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Given :- AB ll EF
ABC = 70
DFE = 40
To find = x
__________________
B = E ( Alternate interior angle )
E = 70
__________________
In triangle DEF
DEF + EFD + EDF = 180 ( Angle sum property )
70 + 40 + EDF = 180
110 + EDF = 180
EDF =180 - 110
EDF = 70
_________________
EDF + X = 180 ( LINEAR PAIR )
70 + X = 180
X = 180 - 70
X = 110
●●●●●●●●●●●●●●●●●●●
HOPE IT HELPS U !!
✌✌
HERE IS YOUR ANSWER,
●●●●●●●●●●●●●●●●●●●
Given :- AB ll EF
ABC = 70
DFE = 40
To find = x
__________________
B = E ( Alternate interior angle )
E = 70
__________________
In triangle DEF
DEF + EFD + EDF = 180 ( Angle sum property )
70 + 40 + EDF = 180
110 + EDF = 180
EDF =180 - 110
EDF = 70
_________________
EDF + X = 180 ( LINEAR PAIR )
70 + X = 180
X = 180 - 70
X = 110
●●●●●●●●●●●●●●●●●●●
HOPE IT HELPS U !!
✌✌
Anonymous:
itni jaldi chali gai :((
Answered by
18
_____________________________
In the following figures,
We have been given with two triangles and their one angle
By this information, we have find out ∠CDF
ANSWER:-
If AB || EF, then ∠ABC = ∠DEF
So,
∠DEF = 70°
∠DEF + ∠EFD + ∠FDE = 180° (A.S.P)
70° + 40° + ∠FDE = 180°
110° + ∠FDE = 180°
∠FDE = 180° - 110°
∠FDE = 70°
∠FDE + ∠CDF = 180° (Linear Pair)
70° + ∠CDF = 180°
∠CDF = 180° - 70°
∠CDF = 110°
Hence, the value of x will be 110°.
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