find value of x if ABCD is a parallelogram.A is 3y,B is 2y-5,C is 3x+3 and D is not given
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Answered by
104
Angle A= 3y°
Angle B= 2y-5°
Angle C= 3x+3°
now Quadrilateral ABCD is a parallelogram then
Angle B=Angle D
Angle D = 2y-5°
angle A+angle B=180
3y+2y-5=180°........................ adjacent angles of a parallelogram
are supplementary
5y=180+5
y=185/5
y=37°
Angle A=37*3
=111°
Angle A= angleC................... opposite
angles of
parallelogram
Angle C=111°................1
but
angleC=3x+3.................2
3x+3=111.....................from 1 and 2
3x=108
x=36
Angle B= 2y-5°
Angle C= 3x+3°
now Quadrilateral ABCD is a parallelogram then
Angle B=Angle D
Angle D = 2y-5°
angle A+angle B=180
3y+2y-5=180°........................ adjacent angles of a parallelogram
are supplementary
5y=180+5
y=185/5
y=37°
Angle A=37*3
=111°
Angle A= angleC................... opposite
angles of
parallelogram
Angle C=111°................1
but
angleC=3x+3.................2
3x+3=111.....................from 1 and 2
3x=108
x=36
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16
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