Question

Find value of x : if log32^x= -3/5​

Answer 1

Answer:

IF LOG IT X base 32=-3/5

X=32^-3/5

X=(2^5^-3/5

X=2^-3

X=1/8

Step-by-step explanation:

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Answer 2

The value of x = 1/8

Given :

$\displaystyle \sf{ log_{32}(x) = - \frac{3}{5} }$

To find :

The value of x

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

$\displaystyle \sf{ log_{32}(x) = - \frac{3}{5} }$

Step 2 of 2 :

Find the value of x

$\displaystyle \sf{ log_{32}(x) = - \frac{3}{5} }$

$\displaystyle \sf{ \implies x = {(32)}^{ - \frac{3}{5} } }$

$\displaystyle \sf{ \implies x = {( {2}^{5} )}^{ - \frac{3}{5} } }$

$\displaystyle \sf{ \implies x = {( {2}^{} )}^{ - \frac{3}{5} \times 5 } }$

$\displaystyle \sf{ \implies x = {( {2}^{} )}^{ - 3} }$

$\displaystyle \sf{ \implies x = \frac{1}{ {2}^{3} } }$

$\displaystyle \sf{ \implies x = \frac{1}{ 8 } }$

Hence the required value of x = 1/8

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