Math, asked by safiay34, 6 months ago

find value of x,if logx216=3​

Answers

Answered by rimaln292
0

Answer:

Step-by-step explanation:Rewrite logx(216)=3 log x ( 216 ) = 3 in exponential form using the definition of ... If x x and b b are positive real numbers and b b ≠ ≠ 1 1 , then logb(x)=y log b ... Substitute the values a=1 a = 1 , b=6 b = 6 , and c=36 c = 36 into the quadratic ..

Answered by Anonymous
29

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find value of x,if logx216=3

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logx216=3

 {x}^{3}  = 216

x =  \sqrt[3]{216}  = 6

x = 6

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