find value of x if sin(x-20)=cos(3x-10)
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Hi mate
here is ur answer
sin(x-20)=cos(3x-10)
let take the x-20 as theta
sin[90-(x-20)]=cos (3x-10)
sin(90-x+20)=cos(3x-10)...... {complementary angles}
cos(110-x)=cos(3x-10)
these cos will get cancelled
110-x=3x-10
120=4x
so, X=30
I hope this will help you
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here is ur answer
sin(x-20)=cos(3x-10)
let take the x-20 as theta
sin[90-(x-20)]=cos (3x-10)
sin(90-x+20)=cos(3x-10)...... {complementary angles}
cos(110-x)=cos(3x-10)
these cos will get cancelled
110-x=3x-10
120=4x
so, X=30
I hope this will help you
⚛️mark as brainliest ⚛️
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