Question

find value of x= x-√6/√3+√2=3√3-4√2/1​

Answer 1

Answer:

VALUE OF X IS 1.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\to \frac{x - \sqrt{6} }{ \sqrt{3} + \sqrt{2} } = 3 \sqrt{3} - 4 \sqrt{2}$

$\: \: \to \sf {x - \sqrt{6} = \sqrt{3} (3 \sqrt{3} - 4 \sqrt{2} ) + \sqrt{2} (3 \sqrt{3} - 4 \sqrt{2} )}$

$\: \: \: \to \sf{x - \sqrt{6} = (9 - 4 \sqrt{6} + 3 \sqrt{6} - 8)}$

$\: \: \to \sf{x - \sqrt{6 } = 1 - \sqrt{6} }$

$\: \: \: \to \sf{x - \sqrt{6} - 1 + \sqrt{6} =0}$

$\: \: \: \to \sf {x \cancel{ - \sqrt{6} + \sqrt{6} } - 1} = 0$

$\: \: \: \to \boxed{ \tt \pink{x = 1 \: is \: the \: answer}}$