Find value of x3 – 8y3 – 36xy - 216, when x = 2y - 6.
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Answered by
0
Answer:
sorry bro it's to harddd
Answered by
2
Answer:
x
3
−8y
3
−36xy−216
=x
3
+(−2y)
3
+(−6)
3
−3(x)(−2y)(−6)
=(x−2y−6)(x
2
+4y
2
+36+2xy−12y+6x)
=0×(x
2
+4y
2
+36+2xy−12y+6x)
=0
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