Question

find value of y+3 is factor p(x)=3y^2+ky +6 and answer is 11

Answer 1

y+3=0

y=-3

put y=-3

3×(-3)²+k×-3+6

27-3k+6=0

-3k=-33

k=-33/-3

k=11

hope it helps you

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Answer 2

Here is ur answer

Y+3=0.

Then y=-3

Substitute to get answer..

P(x) =3(-3)^2+k(-3)+6=0

27+6-3k=0

33=3k

K=11

Therefore value of k=11

3(-3)^2+11(-3)+6=27-33+6=0