Question

Find value of y for which the distance between the points P (2,3) and Q (10,y) is 10units

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Concept:

Distance formula = √( x₂ - x₁ )² + ( y₂ - y₁ )²

Given:

We are given that:

P ( 2 , 3 ) and Q ( 10 , y )

Distance between P and Q = 10 units.

Find:

We need to find the value of y.

Solution:

We will use distance formula for this:

Distance = √( x₂ - x₁ )² + ( y₂ - y₁ )²

Substituting the values:

Distance = √( 10 - 2 )² + ( y - 3 )²

Distance = √ 64 + y² + 9 - 6 y

100 = y² - 6 y + 73

y² - 6 y - 27 = 0

y² - 9 y + 3 y - 27 = 0

y ( y - 9 ) + 3 (  y - 9 ) = 0

( y - 9 )( y + 3 ) = 0

y = 9 or y = -3

Therefore, we get the values of y as -3 or 9 .

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