Question

Find value of y if y=(log1/e)^2

Answer 1

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=> y=(log1/e)^2

=> y = ( log 1 - log e)²

=> y = (0 -1 )²

=> y = (-1)² =1
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Answer 2

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Here is your answer
$y = (log \frac{1}{e} ) {}^{2} \\ y = (log \: 1 - log \: e) {}^{2} \\ y = (0 - 1) {}^{2} \\ y = ( - 1) {}^{2} \\ y = 1$
So Y = 1
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