Find value of y such that (4. y) is 10
units from the point (-2, -1)
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Step-by-step explanation:
distance =✓(-2-4)^2+(-1-y)^2
10=✓36-(1+y)^2
10=✓36-(1+y^2+2y)
squaring on both sides
100=36-1-y^2-2y
y^2+2y=35-100
y^2+2y+65=0
factorise u will get answer
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