Find value of Z using Gauss-elimination method.
x+y+z=4
2x+y+z=5
3x+2y+z=7
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Answer:
z=2
Step-by-step explanation:
(x+y+z=4)+(2x+y+z=5)
=3x+2y+2z=9
(3x+2y+2z=9)-(3x+2y+z=7)
=3x-3x+2y-2y+2z-z=9-7
=0+0+z=2
z=2
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