Question

Find value of Z using Gauss-elimination method.
x+y+z=4
2x+y+z=5
3x+2y+z=7​

Answer 1

Answer:

z=2

Step-by-step explanation:

(x+y+z=4)+(2x+y+z=5)

=3x+2y+2z=9

(3x+2y+2z=9)-(3x+2y+z=7)

=3x-3x+2y-2y+2z-z=9-7

=0+0+z=2

z=2