find value tan 60 geometrically
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Answered by
245
If we consider any right angled triangle ADB, we have
base=BD=a,
perpendicular=AD=√3a,
hypotenuse=AB=2a and ∠ABD=60°
tan60°=AD/BD=√3a/a=√3.
The values of the trig functions of 30° and 60° can be written like this:
(15) sin 30° = ½, sin 60° = (√3)/2. cos 30° = (√3)/2, cos 60° = ½
base=BD=a,
perpendicular=AD=√3a,
hypotenuse=AB=2a and ∠ABD=60°
tan60°=AD/BD=√3a/a=√3.
The values of the trig functions of 30° and 60° can be written like this:
(15) sin 30° = ½, sin 60° = (√3)/2. cos 30° = (√3)/2, cos 60° = ½
Answered by
23
If we consider any right angled triangle ADB, we have
base=BD=a,
perpendicular=AD=√3a,
hypotenuse=AB=2a and ∠ABD=60°
tan60°=AD/BD=√3a/a=√3.
The values of the trig functions of 30° and 60° can be written like this:
(15) sin 30° = ½, sin 60° = (√3)/2. cos 30° = (√3)/2, cos 60° = ½
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